4^(x+1)+8=33(2^x)

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Solution for 4^(x+1)+8=33(2^x) equation: 



4^(x+1)+8=33(2^x)

We move all terms to the left:

4^(x+1)+8-(33(2^x))=0

determiningTheFunctionDomain
4^(x+1)-332^x+8=0

We move all terms containing x to the left, all other terms to the right

4^(x+1)-332^x=-8

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